Equation sin 7x + cos 2x = 2 Solution is A) x=(2kpi)/7 + 3pi/14,kI B) x=npi + pi/4 , n I C)x= 2npi + pi/2 ,n I D)none of these
![f (x) = [ 2x ]sin 3pi x and f ( k^ + ) = lambda kpi (- 1 )^k (where [.]denotes the greatest integer function and k ∈ N ), then find the value of lambda . f (x) = [ 2x ]sin 3pi x and f ( k^ + ) = lambda kpi (- 1 )^k (where [.]denotes the greatest integer function and k ∈ N ), then find the value of lambda .](https://haygot.s3.amazonaws.com/questions/1180933_1113344_ans_ec20bfc403534a058686cd40dfdc3a2e.jpeg)
f (x) = [ 2x ]sin 3pi x and f ( k^ + ) = lambda kpi (- 1 )^k (where [.]denotes the greatest integer function and k ∈ N ), then find the value of lambda .
![Let `z_k = cos(2kpi/10)+isin(2kpi/10); k=1,2,34,...,9` (A) For each `z_k` there exists a `z_j`... - YouTube Let `z_k = cos(2kpi/10)+isin(2kpi/10); k=1,2,34,...,9` (A) For each `z_k` there exists a `z_j`... - YouTube](https://i.ytimg.com/vi/X7nITCeXogI/maxresdefault.jpg)
Let `z_k = cos(2kpi/10)+isin(2kpi/10); k=1,2,34,...,9` (A) For each `z_k` there exists a `z_j`... - YouTube
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